Exactly How the LINE2AMP Reamping Box Works (and Why) July 19, 2012 13:30 19 Comments
Why do we need a reamping box? People have been plugging line-level signals into guitar amps since long before the first reamping box hit the market, often with good results. This is true; in many cases, simply plugging the output of your interface into an amp and crossing your fingers is good enough. However, what we want is to be able to plug any line-level device into any instrument-level input and have it sound right every time. In order to do this, we need a device that addresses the following issues:
- matching volume levels;
- interfacing balanced and unbalanced gear;
- emulating line and instrument impedances;
- ground-related noise.
As so rarely happens in audio and electronics, there is a cheap, simple, and ideal solution to all of these problems: an audio transformer. Let’s look at the ways a humble audio matching transformer can make reamping a consistent and transparent process.
Attenuating the Signal
The nominal level for a professional line-level signals is +4dBu, or approximately 1.2 Volts rms. Guitar signals, on the other hand, vary between a few tens of millivolts rms to 1 Vrms or slightly more depending on the pickup. So, in order to to mimic the output level of an average guitar, we need to attenuate our line-level signal somewhat before sending it to an amp. The clear choice for attenuating voltage (“volume” in audio) in terms of cost and complexity is a couple of resistors set up as a voltage divider. However, since we’re already using a transformer to address the other two problems of reamping, we might as well use it to reduce the voltage as well. Modified and reused under the GNU Free Documentation License
To understand how we can use a transformer to attenuate the signal, let’s look at how transformers work. Transformers operate according to a funny feature of our universe called “electromagnetism” by which a changing electrical field induces a changing magnetic field and vice-versa. A basic transformer such as the one we’re using consists of two coils of conductive wire wrapped around a magnetically permeable core, usually iron. The alternating current running through the “primary” (input) coil creates a magnetic field which induces a corresponding voltage in the “secondary” (output) coil. From our point of view, two important things happen to between the input and output of a transformer. 1) The grounds are isolated (which will be important for solving another reamping problem), and 2) the voltage, current, and impedance are transformed in proportion to the ratio between the number of turns of wire in the two coils (the “turns ratio”). Since the issue at hand is volume, let’s discuss voltage for the moment and leave current and impedance for later. Edcor PC10k/600 transformer
A transformer reduces or increases the voltage of a signal in direct proportion to the turns ratio. If the turns ratio is 2:1, the voltage induced in the secondary will be half of that in the primary. The Edcor PC10k/600 transformer included in the LINE2AMP kit has a turns ratio of 4.1:1, so the output signal is 4.1 times smaller than the input signal. In audio terms, this equates to 12dB of volume attenuation, just enough to get us to an average guitar output level.
Achieving the Correct Impedances
Put simply, “impedance” is the degree to which a circuit opposes the flow of AC current. Impedance is similar to the more basic concept of resistance, except that it is frequency dependent. That is, a circuit may present more opposition to high-frequency than low-frequency signals and vice versa. A great way to de-mystify impedance is to think of it in a realm we're all familiar with: acoustics. Every physical medium presents a certain amount impedance to the propagation of sound. This impedance is not uniform at all frequencies. This is why, for example, we hear the bass drums of a marching band first and higher frequencies connote "presence" to our ears.
There are two impedance values involved when connecting one piece of audio gear to another: that of the output device, called "source" or "output" impedance, and that of the input device, called "load" or "input." These two values tell us (at least) two important things:
- how much of the output signal (voltage) will be transferred to the input device;
- how much power is required for the output device to drive the input device.
Generally speaking, we get optimum results in both of these areas when the output Z is at least 8-10 times lower than the input Z; this is called "bridging" the output impedance. There is a common misconception that the input and output impedances should be matched--forget it, this is not true for audio! So what are the "correct" impedances in a reamping situation? The modern standard for line-level input Z is around 10kΩ, while guitar output Zs vary from below 100Ω for active pickups to 50kΩ+ for passive. In the same way that our transformer induces a different voltage across the secondaries than the primaries, it also transforms impedances. But whereas voltage is transformed in direct proportion to the turns ratio, impedance is transformed in proportion to the square of the turns ratio. Thus, the impedance ratio for our 4.1:1 transformer is 16.81:1, or approximately 10k:600.
We achieve our 10kΩ+ line-level input Z by placing a resistor across the transformer secondaries. The impedance reflected in the primaries is then 16.81 times the value of this resistor (for the LINE2AMP kit I have chosen a 1k resistor). At this point, with only the transformer and 1k resistor, our output Z is equal to the line-level output Z divided by 16.81, i.e., arbitrarily low. We can raise this value to within the range of a typical guitar output Z by adding a resistor in series with the output signal. I chose 15kΩ for this job but any value between 0 (no resistor) and 50k will emulate a different type of pickup.
Balanced to Unbalanced and Ground Noise
Reamping involves interfacing balanced (actually “differential” is correct, but I’ll defer to the parlance of our times) and unbalanced gear. A balanced connection has three parts: signal “hot” (non-inverted, +, tip, XLR pin 2), signal “cold” (inverted, -, ring, XLR pin 3), and ground (shield, chassis, sleeve, XLR pin 1). Balanced gear takes for its signal the difference between the hot and cold signals and ignores anything common to both (including noise). The chassis pin exists to provide unwanted noise a quick path to ground; it is not part of the audio signal.
Modified and reused under the Creative Commons Attribution-Share Alike 3.0 license.Original rendering by Søren Peo Pedersen
An unbalanced signal on the other hand consists of simply signal (tip) and common (“ground,” 0 V, sleeve). In an unbalanced system, the common is the reference for the signal voltage, so any noise injected into the common will in turn affect the signal. In the case of reamping, we are attempting to connect a balanced output from our mixer/interface/whathaveyou to an unbalanced, instrument input. What happens when we do this without properly "unbalancing" the output signal? By connecting the sleeve pins of both devices together we are connecting the the noise return path of the balanced output to the audio common of the unbalanced input. Noise, meet audio. Transformers solve this problem by providing what's called galvanic isolation between the input and output stages. Recall that transformers transfer voltage from one winding to the next through electromagnetic induction, without providing a path for current to flow. Thus, they allow the balanced output stage to "communicate" the signal to the unbalanced input stage without connecting their grounds/commons. It is therefore impossible to a ground loop to exist between the two devices. That's it. An elegant solution to a simple problem. Please feel free to continue this discussion below with your questions, comments or corrections.
Comments
Jay on November 12, 2014 18:03
If I were to emulate a pickup output with a DC resistance of 14.6 k (as my multimeter says my duncan SH-10 is) what equation leads me to the value of the resistor I require? Or how would I emulate a medium-high output pickup without replacing the transformer?
Peterson Goodwyn on November 12, 2014 18:03
Hi Jay, good question. While there is some output impedance inherent before adding an output resistor, it’s pretty much low enough to ignore. So, to achieve a DC-resistance/output impedance of around 14.6k all you need is a 14.6k resistor.
However! I’m very skeptical about the affect a simple output resistor has on the sound. A purely resistive output impedance is linear w/r/t frequency and serves only to reduce the amount of voltage transfered to the input device. So, while many folks focus on DC-resistance as something important in the sound of a guitar, it’s really the interaction of that resistance with the inductance of the pickup and the capacitance of the cable that gives a guitar is non-linear sonic signature. This is why there will be a “Passive Pickup Emulator” option with the LINE2AMP Rev C and why I don’t think you should sweat the value of the output resistor too much.
Steve on November 12, 2014 18:03
Simply ace may I use this with my students at college?
Peterson Goodwyn on November 12, 2014 18:03
I love that idea! Please let me know how it goes.
Nick on November 12, 2014 18:03
I thought that the line2amp would be perfect for my use, but now I’m not sure – I actually want to get from my console (balanced out) to a computer (unbalanced in).
Not sure about the resistor values to get the correct impedance, but this is a necessity to isolate the console from the computer – too much noise with a direct connection.
Any suggestions?
Peterson Goodwyn on November 12, 2014 18:03
Hi Nick, sorry for the delayed response. Since you are running a line out from your console to a line in on your computer, the impedances should be correct to start with.
If you are getting a lot of noise, it may be because of the nature if interfacing balanced and unbalanced gear. By plugging a balanced signal into your unbalanced computer jack, you are connecting the chassis ground of the balanced system with the signal common of the unbalanced. You might be able to fix this by simply making a dedicated balanced to unbalanced adapter cable. Check out Figure 3 in this excellent Rane note on the subject: http://www.rane.com/note110.html
Keith on November 12, 2014 18:03
Curious as to the functional differences between theLine 2 Amp and the Ferrite DI, besides the obvious transformer. What makes a re-amping box different from a DI? Do they sort of work in reverse of each other?
Nick on November 12, 2014 18:03
I currently am using Rane’s modded cable version, but would like to a transformer to isolate it because there is an unacceptable amount of noise from the computer. What type of transformer would I be looking for? If impedance stays the same I’m guessing a 1:1?
Peterson Goodwyn on November 12, 2014 18:03
Exactly. Check out something like the Edcor WSM10k:10k.
Peterson Goodwyn on November 12, 2014 18:03
Great question. The answers is that, yes, they sort of work in reverse of each other, but not really. Let’s break it down:
A reamp box takes a balanced, line-level signal input and gives an unbalanced, instrument-level output. It must present a moderately high input impedance (10k) and rather high output impedance (15k for the LINE2AMP). We also want a small volume decrease, which requires a low-ratio step-down transformer (or a 1:1 transformer with a pad following it).
A DI takes an unbalanced, instrument-level input and gives a balanced, microphone-level output. It must present a very high input impedance (130k or so for a passive DI) and very low output impedance (around 200 Ohms). This impedance transformation requires a very “steep” step down transformer with a ratio of around 12:1.
So, let’s look at what happens when you use a passive DI in reverse (active DI won’t work). Our balanced line-level input goes into the “output” side of the DI transformer, which is designed for mic-level signals. This may overload the transformer. Then the signal gets stepped up by a ratio of 1:12 before going to the output. In most cases, this will be way too much signal for a guitar input to handle.
The input impedance of the “reverse DI” may also be unacceptably low. Our input impedance is determined by that of the guitar amp or pedal following the reverse DI, modified by a ratio of 144:1. (Remember that transformers change the impedance by the square of the turns ratio—a change of 144:1 for our 12:1 transformer.) So, even if the guitar amp/pedal has an exceptionally high input impedance of 1M Ohms, the our reverse DI will reflect an input impedance of only 6.94k Ohms—lower than the recommended standard of 10k for line-level inputs.
So there you have it. While passive DI’s and reamping boxes may be superficially similar, they’re actually designed to meet very different requirements and do not work very well in reverse.
Fredrik on November 12, 2014 18:03
This article is really great, and I really appreciate it. I still don’t really understand what impedance is in practise. I know it’s reactance + resistance etc, but I find it is hard to understand what it really is. I have actually googled the subject without great success, so I was wondering if you had any suggestions. Thank you
Peterson Goodwyn on November 12, 2014 18:03
Hi Fredrik, without getting too deep into what could be a big subject, here’s my simple understanding of impedance. (Keep in mind I’m not a certified EE, just an audio guy trying to make sense of this stuff.) Impedance is the degree to which something impedes the flow of AC current. You probably know that definition already, but what does it really mean from an audio standpoint?
When one audio device is hooked up to another, the first in the chain is the “source” which “drives” the second device in the chain, the “load.” It is the job of the source to provide current and to drive the load. Different sources can provide different amounts of current, while different loads require different amounts of current to be driven. This is what output and input impedance mean.
More impedance means less current. A source with a high output impedance can provide less current, while a load with a higher input impedance requires less current. And vice-versa. Take for example a standard power amp and speaker setup. The power amps are designed to provide a lot of current, so they typically have very low output impedances (below 1Ohm). Speakers require a good amount of current, so they have a fairly low input impedance. Here’s a mystery for you: which requires more current, an 8 Ohm or 4 Ohm speaker?
Look at a very different case. Guitar amps have very high input impedances, often around 1M Ohm. Why do you think this is? Because passive guitar pickups do not provide a lot of current. Which is the exact same as saying they have a very high output impedance. Therefore, the input impedance of the load (the guitar amp) must be very high so that it will not try to draw too much current from the guitar.
Is this starting to paint a clearer picture?
Fredrik on November 12, 2014 18:03
Yes, indeed! Thank you very much for explaining. This is by far the best practical explanation I’ve read. Thanks:)
Chris on November 12, 2014 18:03
This is a similar question to Keith’s about the di. Is it possible to use the line2amp in a reverse fashion. Would i be able to take an ouput from a delay pedal and go into the line2amp in reverse then into a line level input for a mixer or soundcard?
Like for using a pedal or pedal chain going into the aux fx bus of a mixer.
Sorry if this is a stupid question.
Peterson Goodwyn on November 12, 2014 18:03
Hi Chris, this is a great question. As with Keith’s question, the answer is that the LINE2AMP in reverse will do the job you’re describing, but it’s not ideal. The part of the problem you probably have in mind—going from unbalanced out to balanced in—is what the LINE2AMP will do perfectly.
Impedance is where it gets messy. Since the transformer has a ratio of 4:1 the output impedance when used in reverse will be 16x higher than the input (turns ratio squared) and the input impedance will be 16x lower than that of the line input. A higher output impedance and lower input impedance means the fx pedal will have to work much harder to drive the line input, resulting in a weak, distorted signal.
Duncan on November 12, 2014 18:03
I’ll chime in (better late than never) with a really good reason for a re-amp. The balanced output of some equipment comes straight off an opamp with a series resistor to make it match impedance (300 Ohm per leg = 600 Ohm total.)
When you use a tip/ring/sleeve 1/4" jack to adapt balanced to unbalanced, you get the “cold” output shorted straight to signal ground. Ouch. That 300 Ohm resistor on the negative phase/cold opamp makes that opamp work harder than it has to. Many circuits will allow the now higher distortion due to overload to bleed over to the hot side circuit. This is a bad thing.
That’s all I wanted to say, don’t shortcut the balanced/unbalanced interface, it can cost you overhead.
Tom Wilkowske on November 12, 2014 18:03
Can you explain how this unit is similar to / different from a DI / Direct Box?
Raphael on November 12, 2014 18:03
Hi there,
I want to use a Line6 M13 effect pedal (digital) on Aux out of a Midas Venice F24 (output is 50ohm). As you may expect it’s heavily clipping the M13 input. Awful. Then I used a friend’s Radial ProRMP re-amper, but still I had to turn down the output level knob (on the RMP) quite a lot in order to achieve no distortion when the Aux knob is at unity on the mixer.
Could I add a trim knob inside a LINE2AMP ? Would that compromise anything (impedance, etc) ?
I would need 3 LINE2AMP just for interfacing that M13, so I would like to know that before I pull the trigger and order them…
Peterson Goodwyn on November 12, 2014 18:03
Hi Tom, great question. A DI box converts an unbalanced, guitar-level signal to balanced, microphone-level. A re-amplifier converts from balanced, line-level to unbalanced, guitar-level while isolating the grounds of the two sides to prevent noise.
Comments are closed for this post.